Aconcrete column has a diameter of 350 mm and a length of 2 m. if the density (mass> volume) of concrete is 2.45 mg> m3, determine the weight of the column in pounds.

Density is defined as mass per unit volume. If we know the volume and he density we can calculate the mass by simply multiplying density and volume.

Density given = 2.45 mg/m^3 . [ I feel this should be Kg/m^3, Kindly check. Here I will solve it with what is given]

volume of cylinder = pi.r^2.h

r = d/2 = 175mm = 0.175m

h = 2m

Volume = 0.192 m square

mass = density x volume

mass = 0.192 x 2.45

= 0.470mg. {should be Kg if density is in Kg/m^3]

The weight of the column is 10.2pounds

Explanation:

Step one

Given data

Diameter of column d=350mm

Radius =d/2=175m

length of column h =2m

Density of concrete =2.45 mg/m3

mg

The shape of the column is a cylinder

Volume of a cylinder =pi*r²*h

Volume of concrete =3.142*175²*2

Volume =192447.5m³

We know that the density of a substance is =mass/volume

First Let's find the mass

2.45*10^-6=mass/192447.5

mass=2.45*10^-6*192447.5

Mass=0.47149638kg

Mass=0.47kg

Converting to pound

1kg=2.20 5 pounds

0.47kg=x

Crosss multiplying we have

X=0.47*2.205

X=1.04pounds

But weight =m*g

Assuming g=9.81m/s

Weight =1.04*9.81

Weight =10.2pounds

it has to be b, about 97 percent.