Atrain starts from rest and travels for 5.0 s with a uniform acceleration of 1.5 m/s 2. how far does the train travel in this time interval?

Given: Initial velocity of train (u) = 0

Acceleration of train (a) = 1.5 m/s²

Travel time (t) = 5.0 s

To Find: The distance traveled by train in the given time interval

Formula Used: 2nd kinematic equation of motion

s = ut + (1/2) at²

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Now, using equation (i), we shall calculate the value of s

                     s = 0×5.0 + (1/2) ×1.5×(5.0)² m

or,                 s = 18.75 m

Hence, the required traveled distance by the train will be 18.75 m.

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hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.