Amodel rocket blasts off and moves upward with an acceleration of 12 m/s2 until it reaches a height of 26 m. at that height, its engine shuts off, and it continues its flight in free fall. (a) what is the maximum height attained by the rocket? (b) what is the speed of the rocket just before it hits the ground? (c) what is the total duration (ins) of the rocket's flight?

initial acceleration of rocket is given as

a = 12 m/s^2

h = 26 m

now we can use kinematics to find its speed

now after this it will be under free fall

so now again using kinematics

at maximum height

total height from the ground = 31.8 + 26 = 57.8 m

Part b)

now after reaching highest height it will fall to ground

So in order to find the speed we can use kinematics again

Part c)

first rocket accelerate to reach height 26 meter and speed becomes 24.98 m/s

now we have

after this it will reach to highest point and final speed becomes zero

now from this it will fall back to ground and reach to final speed 33.67 m/s

now we have

so total time is given as

t = 3.44 + 2.55 + 2.1 = 8.1 s

multiply 2kg by latent heat of vap

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge