Suppose that a shot putter can put a shot at the worldclass speed v0 = 15.00 m/s and at a height of 2.160 m. what horizontal distance would the shot travel if the launch angle θ0 is (a) 45.00° and (b) 42.00°? the answers indicate that the angle of 45°, which maximizes the range of projectile motion, does not maximize the horizontal distance when the launch and landing are at different heights.

Part a

Horizontal Distance: 22.5 m

Velocity at which shot putter shot

Angle at which it was shot =

Time of flight is given by the formula:

Taking accleration due to gravity,

Then, Horizontal distance is given as:

Part b

Horizontal distance= 23.86 m

Velocity at which shot putter shot

Angle at which it was shot =

Time of flight is given by the formula:

Taking accleration due to gravity,

Then, Horizontal distance is given as:

Therefore, although the range is maximum for part a but horizontal distance covered is smaller than in part b.

the skeletons of most mammals reach a certain size and then stop growing. however, many animals, including some mammals, keep growing throughout their lives. kangaroos, for example, just keep growing and growing until they die. also, the longer an animal lives the greater the chance it might catch some deadly disease.