The highest barrier that a projectile can clear is 12.2 m, when the projectile is launched at an angle of 13.0 ° above the horizontal. what is the projectile's launch speed?

consider the motion in vertical direction

v = initial velocity in the vertical direction = ?

v' = final velocity in the vertical direction at the highest point = 0 m/s

a = acceleration due to gravity = - 9.8 m/s²

h = maximum height = 12.2 m

Using the kinematics equation

v'² = v² + 2 a h

0² = v² + 2 (- 9.8) (12.2)

v = 15.5 m/s

let assume that velocity of launch be v₀

θ = angle of launch = 13

vertical component of the velocity of launch is given as

v = v₀ Sinθ

15.5 = v₀ Sin13

v₀ = 69 m/s

most of them using statistics and defining how things are being measured

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.