Aball is dropped from rest from a height h above the ground. another ball is thrown vertically upwards from the ground at the instant the first ball is released. determine the speed of the second ball if the two balls are to meet at a height h/2 above the ground. (use h and g as appropriate in your equation.)

The initial velocity of the second ball is m/s.

Given that a ball is dropped from rest from a height h above the ground. This ball has acceleration equal to gravitational acceleration. The position of the first ball for the time t is given below.

Another ball is thrown vertically upwards from the ground at the instant the first ball is released. Let consider that the initial velocity of the second ball is v and acceleration is equal to gravitational acceleration. The position of the second ball for the time t is given below.

If the two balls are to meet at a height h/2 above the ground. Their position will be the same at the meeting point. It means that,

Substituting the value of x1 in the above equation, we get time t as given below.

Substituting the value of t and x2 in the above equation, we get the initial velocity v of the second ball.

Hence we can conclude that the initial velocity of the second ball is m/s.

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The position of the first ball is

while the position of the second ball, thrown with initial velocity , is

The time it takes for the first ball to reach the halfway point satisfies

We want the second ball to reach the same height at the same time, so that

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

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