Aparticle's velocity is described by the function vx = t 2 - 7t + 10 m/s, where t is in s. a. at what times does the particle reach its turning points? b. what is the particle's acceleration at each of the turning points?

The turning point of the particle is at 3.5 seconds with an acceleration of 0.

Acceleration is the time rate of change of velocity. It is given by the equation:

Acceleration = change in velocity / change in time

Given the velocity equation:

v = t² - 7t + 10

The turning point is at dv/dt = 0, hence:

dv/dt = 2t - 7

2t - 7 = 0

t = 3.5 seconds

Acceleration (a) = dv/dt

a = 2t - 7

a(3.5) = 2(3.5) - 7 = 0

The turning point of the particle is at 3.5 seconds with an acceleration of 0.

Find out more on Acceleration at: link

velocity is given as

when the object reached to its turning its velocity will be zero

so it will reach its turning at two time instant

Part b)

For acceleration we know that

now at t = 2

also at t=5

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explanation:

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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