Consider a lawnmower of mass m which can slide across a horizontal surface with a coefficient of friction μ. in this problem the lawnmower is pushed using a massless handle, which makes an angle θ with the horizontal. assume that fh, the force exerted by the handle, is parallel to the handle. take the positive x direction to be to the right and the positive y direction to be upward. use g for the magnitude of the acceleration due to gravity.

The magnitude of the force required to slide the lawnmower over the ground is

Consider the movement of the lawnmower of mass (m) which slides across a horizontal surface in the horizontal direction;

In the horizontal direction, the net force is:

where;

In the vertical direction, the net force is:

replacing the value of N in the second expression into the first part, then we have:

Therefore, we can conclude that the magnitude of the force required to slide the lawnmower over the ground is

Learn more about the magnitude of the force here:

link

Applied force is Fh at an angle theta with the horizontal

now we will have its components

now in order to find the normal force

we will have

now we can find friction force

now in order to move the lawn mover

now we will have

so above is the force on it

answer; i believe that the correct answer is (d) a very small amount of mass

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.