Abasketball player hits a baseball which just clears a 7.50 m high, located 90.0 m away from home plate. if the ball was hit 1.0 m of the ground at an angle 35 degree, what was the initial speed of the baseball?

Let be the initial velocity of the ball. Then it has components

The position vector of the ball at time has components

where is the acceleration due to gravity. When the ball is 90.0 m away from home plate, we're told that it clears (presumably) a barrier of some kind that is 7.50 m tall, so that for some time we get

Solving for this gives

Substituting this into the second equation gives

this is a good question! i'll do some research and come back when i have the answer!