Acar is traveling north at 17.7 m/s . after 6 it’s velocity is 141 in the same direction. find the magnitude and direction of the cars average acceleration

By equation of motion we have   v = u + at

Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration

Here v = 141 m/s, u = 17.7 m/s and t = 6 s

On substitution we will get

        141 = 17.7+ 6a

       So, a = (141-17.7)/6 = 20. 55 m/

       Aceeleration = 20. 55 m/ along north direction.

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