Turner's treadmill runs with a velocity of -1.3 m/s and speeds up at regular intervals during a half-hour workout. after 25 min, the treadmill has a velocity of -6.5 m/s. what is the average acceleration of the treadmill during this period ?

Given : Initial velocity = -1.3 m/s

            Final Velocity = -6.5 m/s.

            Time = 25 minutes.

To find : Average acceleration.

Solution: We are given units in meter/second (m/s).

So, we need to convert time 25 minutes in seconds.

1 minute = 60 seconds.

25 minutes = 60*25 = 1500 seconds.

Formula for average acceleration is given by,

We are not given intial time, so we can take initial time =0.

Plugging values in the above formula.

=

= -0.003467

or .

The average acceleration of the treadmill during this period is 0.00346 m/s²

Explanation:

It is given that,

Initial velocity of the treadmill, u = 1.3 m/s

After 25 minutes, the treadmill has a velocity of 6.5 m/s

Final velocity of the treadmill, v = 6.5 m/s

Time taken, t = 25 minutes = 1500 seconds

We need to find the average acceleration of the treadmill during this period. It is given by :

So, the average acceleration of the treadmill during this period is 0.00346 m/s². Hence, this is the required solution.

a displacement distance is size of displ

unbalanced force

explanation: