Optimus decides to throw megatron down of a building at 5.0m/s. megatron hits the ground at 32.0m/s- how long does it take to hit the ground? - how far does he fall?

We have equation of motion v = u+at, where v is the final velocity, u is the initial velocity, t is the time taken and a is the acceleration.

Considering vertical motion of megatron

Here u = 0 m/s, a= 9.81 and v = 32 m/s

Substituting

     32 = 0+9.8*t

      t = 3.27 seconds

So it will take 3.27 seconds to reach ground.

Now considering horizontal motion of megatron

We have , where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

In this case u = 5 m/s, t = 3.27 seconds, a = 0

Substituting

So Megatron falls 16.35 meter away from ground.

b would be the answer

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form