As a tennis ball is struck, it departs from the racket horizontally with a speed of 28.0 m/s. the ball hits the court at a horizontal distance of 19.6 m from the racket. how far above the court is the tennis ball when it leaves the racket?

The tennis ball is "2.401 m" far.

According to the question,

Horizontal distance = 19.6 m

Horizontal speed = 28

The time taken by the ball be:

→ t =

By substituting the values,

    =

    = second

By using equation of motion, we get

→ s = ut + gt²

By substituting the values,

     =

     = m

Thus the above answer is right.

Find out more information about Equation of motion here:

link

solution:

long to travel 19.6m at 28m/s

t =19.6/28

=time taken to drop from rest

s=ut+(1/2)at^2

u=0

a=~10

so s=(1/2)*10*(19.6/28)^2 =2.45m

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!

yo yo yo its papaguy in the house lol

okay, ima .

um it shows links to uh so kinda microsoft website is that were ima go or no? ?