David is driving a steady 25.0 m/s when he passes tina, who is sitting in her car at rest. tina begins to accelerate at a steady 2.40 m/s2 at the instant when david passes.

Answer;

= 520.833 m

Explanation and solution;

Assuming D is at 25 m/s; T's acc = 2.4 m/s2  

let time be t and distance be d  

for D,  

25 × t = d  

t = d/25 (1)  

for T,  

u=0  

s= ut + 0.5 at^2  

d = 0 + 0.5 × 2.4 × t^2  

d = 1.2 t^2 (2)  

(1) sub into (2)  

d = 1.2 × [d/25]^2  

d = 0.00192 d^2  

d = 520.833 m

lexy is right because she has the labeled s

terd muffin is the correct answer