In a slap shot, a hockey player accelerates the puck from a velocity of 8.00 m/s to 40.0 m/s in the same direction. if this shot takes 3.33×10 −2 s, calculate the distance over which the puck accelerates.

We use the equations of motion,

                                              (A)

                               (B)

Here, v is final velocity of the body, u is initial velocity of the body, a is the acceleration of the body, t is the time taken in the motion and s is distance traveled by the body.

Given , and .

So, from equation (A)

Now from the  equation (B),

Thus, the distance over which the puck accelerates is 0.8 m.

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