Avery small object carrying -6.0 μc of charge is attracted to a large, well-anchored, positively charged object. how much kinetic energy does the negatively charged object gain if the potential difference through which it moves is 3.0 mv

    Kinetic energy gain by a very small object carrying -6.0 μc of charge is attracted to a large, well-anchored, positively charged object = 18 nJ

Explanation:

  The potential energy gained by negatively charge is the change in potential energy between the points.

 So, Kinetic energy = Change in potential energy = qΔV

 In this case q = 6.0 μc = and ΔV = 3.0 mV =

  Substituting

              Kinetic energy gain =

electrical to thermal

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