Bruce (the dog) is pulling on his lead with a force of 40n at an angle of 26º below the horizontal. show that the horizontal component of this force is about 36n.

The horizontal component of this force is about 36 N.

Explanation:

Given that,

Bruce is  is pulling on his lead with a force of 40 N

Angle below horizontal,

We need to find the horizontal component of this force. The horizontal component of any vector is given by :

or

So, the horizontal component of this force is about 36 N. Hence, this is the required solution.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y