If 2050 j of heat are added to a 150 g object its temperature increases by 15°c. (a) what is the heat capacity of this object? (b) what is the object's specific heat?

When an object gets heated by a temperature ΔT energy needed, E = mcΔT

Here energy is given E = 2050 J

Mass of object = 150 g

Change in temperature ΔT  = 15 = 15 K

a) Heat capacity of an object equal to the ratio of the heat added to (or removed from) an object to the resulting temperature change.

  So heat capacity = E/ΔT = 2050/15 = 136.67 J/K

b) We have E = mcΔT

                    c =

 So object's specific heat = 911.11 J/kgK

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