Ccording to coulomb's law, which pair of charged particles has the lowest potential energy? according to coulomb's law, which pair of charged particles has the lowest potential energy? a particle with a 1− charge separated by 100 pm from a particle with a 3+ charge. a particle with a 1− charge separated by 100 pm from a particle with a 2+ charge. a particle with a 1− charge separated by 200 pm from a particle with a 1+ charge.

The electrostatic potential energy of a particle with a 1− charge separated by 200 pm from a particle with a 1+ charge.

Explanation:  

The formula for the electrostatic potential energy is as follows;

Here, U is the potential energy, are the charges and r is the distance between them.

Here,

is the absolute permittivity of free space.

Calculate the electrostatic potential energy of a particle with a 1− charge separated by 100 pm from a particle with a 3+ charge.  

Put q_{1}=-1, q_{2}=+3,k= and r=100 pm.

Calculate the electrostatic potential energy of a particle with a 1− charge separated by 100 pm from a particle with a 2+ charge.

Put q_{1}=-1, q_{2}=+2 and r=100 pm.

Calculate the electrostatic potential energy of a particle with a 1− charge separated by 200 pm from a particle with a 1+ charge.

Put q_{1}=-1, q_{2}=+1 and r=200 pm.

Therefore, the electrostatic potential energy of a particle with a 1− charge separated by 200 pm from a particle with a 1+ charge.

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)