Apaintball is shot horizontally in the positive x direction at time t after the ball is shot it is 4 cm to the right and 4 cm below its starting point at time 2 t what is the position of the ball relative to its starting point ignore air resistance

At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom

Explanation:

 We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering the horizontal motion of paint ball

    Distance traveled during time t = 4 cm

    Initial velocity = u m/s

   Acceleration = 0

So

Now at time 2t,

  So horizontal distance traveled in time 2t = 8 cm to the right

Now considering the vertical motion of paint ball

  Distance traveled during time t = 4 cm

    Initial velocity = 0 m/s

   Acceleration = -g

At time 2t,

 So vertical distance traveled in time 2t = 16 cm to the bottom

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