An airplane flies between two points on the ground that are 500 km apart. the destination is directly north of the origination of the flight. the plane flies with an air speed of 120 m/s. if a constant wind blows at 10.0 m/s due west during the flight, what direction must the plane fly relative to the air to arrive at the destination?

 Plane must fly 4.78⁰ due north to east at a speed of 120 m/s to reach destination.

Explanation:

  Let the east point towards positive X-axis and north point towards positive Y-axis.

  Speed of plane = 120 m/s

  Wind speed  = 10.0 m/s due west  = -10 m/s

  So plane must have an horizontal speed of 10 m/s to cancel this wind speed

  Horizontal speed of plane = u cos θ = 120*cos θ = 10

  Angle θ =85.22⁰ from positive horizontal axis.

  Angle from North axis towards East required = 90 - 85.22 = 4.78⁰

 So plane must fly 4.78⁰ due north to east at a speed of 120 m/s to reach destination.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

false

explanation: