Arowboat crosses a river with a velocity of 3.30 mi/h at an angle 62.5â° north of west relative to the water. the river is 0.505 mi wide and carries an eastward current of 1.25 mi/h. how far upstream is the boat when it reaches the opposite shore?

 Rowboat arrives 0.558 miles to the upstream when it reaches the opposite shore.

Explanation:

   Velocity of rowboat = 3.30 mi/h

   Angle with north of west = 62.5⁰

   Width of river = 0.505 mile.

   Velocity of river = 1.25 mi/hr eastward.

Let us take east as positive X -axis and North as positive Y-axis.

   So angle of boat with horizontal axis = (90+62.5) = 152.5⁰

  Horizontal speed of boat = 3.30*cos 152.5 = -2.93 mi/h

  Vertical speed of boat = 3.30*sin 152.5 = 1.52 mi/h

  Horizontal speed of river = 1.25 mi/h

  Time taken to cross river = Width of river/Vertical speed = 0.505/1.52 = 0.33 hour.

  Velocity along upstream of river = -2.93+1.25 = -1.68 mi/hr

  So distance moved along upstream = -1.68*0.33 = -0.558 miles ( negative sign means along west direction)

  It reaches 0.558 miles to the upstream when it reaches the opposite shore.

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.