Apitcher throws a fastball horizontally toward home plate 18.39 meters away. if the ball is traveling at a speed of 40.0m/s, neglecting air friction, how long does it take for the ball to get to home plate

The time taken by the ball to cover the distance between the pitcher and the home plate is 0.459 sec.

Given to us

Distance between pitcher and home plate = 18.39 meters

speed of the ball = 40 m/s

The time taken by the ball to cover the distance between the pitcher and the home plate can be found out using the relationship between speed, distance, and time relationship.

Substitute the values

Hence, the time taken by the ball to cover the distance between the pitcher and the home plate is 0.459 sec.

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you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m