An object is fired from the ground at 200 meters per second at an angle of 30* with the horizontala. calculate the horizontal and vertical components of the initial velocityb. after 6.0 seconds how far has the object traveled on the horizontal directionc. how high is the object at this point

Horizontal component = V cos(30°) = V (√3/2) = 73.2 m/s

Vertical component = V sin(30°) = V (0.5) = 100 m/s

In 6 seconds, the object travels horizontally (173.2 m/s x 6 sec) = 1,039 m

After 6 seconds, the object's height above the ground is

H = V₀t + 1/2 a t²

H = (100 m/s)(6 s) + (1/2) (-9.8 m/s²) (6 s)²

H = (600 m) - (4.9 m/s²) (36 s²)

H = (600 m) - (176.4 m)

Height = 423.6 m

33: i think it’s b

i need the answer to this too but idk it ; -;