An 80-kg fireman slides 5.0m down a fire pole. he holds the pole, which exerts a 500-n steady resistive force on thr fireman. at the bottom he slows to a stop in 0.40m by bending his knees. what can you determine using thos information?

Quite a few things can be determined using this information.

(i) First, we can calculate the Weight of the fireman using W = mg.

We get its magnitude as W = (80)(9.8) = 784 N

(ii) While his Weight is responsible for pulling him down, the pole exerts a constant Resistive Force that is given to be 500 N.

We can calculate the Net Force acting on the fireman as

We get its numerical value to be

(iii) Using this, we can calculate the acceleration with which he slides down the pole from Newton's 2nd law equation as

Therefore,

(iv) With this acceleration, he slides down a distance of 5.0 m - 0.4 m = 4.6 m before he starts applying an additional force with his knees.

We can calculate the velocity he attains just before bending his knees using the following data:

Initial Velocity at the top of the pole

Vertical displacement down the pole D = 4.6 m

Acceleration

Final Velocity

Using the equation

Plugging in the numbers, we have

Thus, we get the value of as 5.72 m/s

(v) This velocity serves as the initial velocity for the part of the journey with his knees bent.

We can calculate the acceleration he has using the following data:

Initial Velocity m/s

Final Velocity

Displacement during the last part of the journey D = 0.4 m

Acceleration a = ?

Again using the equation , and plugging in the known numbers, we get

Hence,

(vi) We can calculate the Net Force acting on him during this part of the journey as

(vii) Since the Net Force is the vector sum of Weight, Resistive Force, and the additional Knee Force, we can write them as

Solving for Knee Force gives its magnitude to be 3555.84 N.

Thus, the fireman begins applying an additional 3,556 N force to stop himself in 0.4 m.

(viii) We can even calculate the time taken for the entire journey. We will deal with it in two parts.

For part one, the following information can be used:

Initial Velocity

Final Velocity

Acceleration

Time taken t = ?

Using the equation , we get the time taken as 1.6 seconds.

For the second part of the journey, the following information can be used:

Initial Velocity

Final Velocity

Acceleration

Time taken t = ?

Using the equation again, and plugging in the appropriate values, we get the time taken as 0.14 seconds.

Hence, the total time the fireman took to slide down the 5.0 m pole is 1.74 seconds.

Hope this helps!

does anyone know or what?

answera compound;