Asailboat starts from rest and accelerates at a rate of 0.13 m/s2 over a distance of 458 m. (a) find the magnitude of the boat's final velocity. m/s (b) find the time it takes the boat to travel this distance. s

Given:

u(initial velocity): 0

a(acceleration): 0.13 m/s∧2

distance = 458 m

Now  s= ut +1/2 (at∧2)

Substituting from the given values we get

458= 0+ 1/2(0.13 x t∧2)

t = 83.94 secs

Now v (velocity)= u+ at

Substituting for t as 83.94 secs and for a and u from the given values we get:

v= 0+0.13 x t

v= 0.13 × 83.94

v=10.91 m/s

Therefore the final velocity of the boat is 10.91 m/s and the time taken for the boat to travel 458 m is 83.94 secs

the answer is a 3.8cm

explanation:

the force on the thing and the distance the force moves the thing