Acurrent of 0.2 a flows through an electric bell having a resistance of 65 ohms. what must be the applied voltage in the circuit?

Now we know by Ohm's law that

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

Introducing the constant of proportionality, the resistance,the Ohm's law can be mathematically represented as

V=I x R

Where V is the voltage measured in volts

I is the current measured in amperes

R is the resistance measured in ohms

Given:

I = 0.2 A

R= 65 ohms

Now substituting the values in Ohm's law we get

V = I x R

V = 0.2 x 65

V = 13 volts

electric

explanation:

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

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