Ago-cart travels the first half of a 100m track with a constant speed of 5.00m/s. in the second half of the track, it experiences a mechanical problem and slows down at 0.200m/s^2. how long does it take the go cart to travel the 100m distance. explain why two different answers.

Total time taken to travel 100 m = 23.82 seconds

In first case the velocity is constant and in the second case velocity is reducing by 0.2 m/s each second, so time taken will be different.

Explanation:

 A go-cart travels the first half of a 100m track with a constant speed of 5.00m/s

Time taken for first half of 100m = Distance velocity = 50/5 = 10 seconds

We have equation of motion , where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

 For the second half of 100m we have

   s = 50 m, u = 5 m/s, a =

Substituting

 t = 13.82 seconds or t = 36.18 seconds

 So it will take 13.82 seconds to travel second 50m

Total time taken = 10 + 13.82 = 23.82 seconds

In first case the velocity is constant and in the second case velocity is reducing by 0.2 m/s each second, so time taken will be different.

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explanation:

d is the correct answer