Asquare metal plate 1.5m side and 1.2mm thick weighting 50n is to be lifted through a vertical gap at 25mm of infinite extent . the oil in air gap has a specific gravity of 95 percent and viscosity of 2.5n. s/m^2. if the metal plate is to be lifted at a constant speed of 0.1m/s find the force and power required.

Viscous force on the plate is given by

Buoyancy force on the plate is given as

Weight of the plate = 50 N

Now for constant speed of plate the net force on it must be zero

SO here we can say

So it will require a constant force of 493.6 N

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down