Anegative charge, q1, of 6 µc is 0.002 m north of a positive charge, q2, of 3 µc. what is the magnitude and direction of the electrical force, fe, applied by q1 on q2? a) magnitude: 8 × 10^1 n direction: south b) magnitude: 8 × 10^1 n direction: north c) magnitude: 4 × 10^4 n direction: south d) magnitude: 4 × 10^4 n direction: north

D. magnitude: 4 × 104 N

direction: north

D) magnitude: 4 × 10^4 N

direction: north

Explanation:

q₁ = magnitude of negative charge = 6 x 10⁻⁶ C

q₂ = magnitude of positive charge = 3 x 10⁻⁶ C

r = distance between the two charges = 0.002 m

Magnitude of electric force between the two charges is given as

F = k q₁ q₂/r²

where k = constant = 9 x 10⁹

inserting the values

F = (9 x 10⁹) (6 x 10⁻⁶) (3 x 10⁻⁶)/(0.002)²

F = 4 x 10⁴ N

magnitude : 4 x 10⁴ N

Direction : North

we know that a negative charge pulls a positive charge towards it. the negative charge "q₁" is north of the positive charge. hence the charge q₁ apply force on charge q₂ in north direction.

emily ruth's annual premium is $1058.50

step-by-step explanation:

emily ruth is a female of 27 years age purchasing 20 year endowment insurance with face value $25000.

from the given table,

for females, the age of a male 3 years younger should be used.

so, we have to check for 24 year male for 20 year endowment.

it is 42.34 for every $1000 face value.

for a face value of $25000,

it is 25 * 42.34 = $1058.50

∴ emily ruth's annual premium is $1058.50