Acharge of +0.08 c moves to the right due to a 4 n force exerted by an electric field. what is the magnitude and direction of the electric field? a) 0.32 n/c left b) 0.32 n/c right c) 50 n/c left d) 50 n/c right

Electric field, E = 50 N/C right

Explanation:

It is given that,

Magnitude of charge, q = +0.08 C

Force exerted on it by an electric field is, F = 4 N

This charge is moving to the right due to 4 N force which is exerted by an electric field. Electric force per unit electric charge is called electric field. Mathematically, it can be written as :

E = 50 N/C

The electric of electric field is same as direction of electric force. So, the correct option is (d) " E = 50 N/C right ".

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i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.