Two horses begin at rest. after a few seconds, horse a is traveling with a velocity of 10m/s west, while horse b is traveling with a velocity of 13m/s west. which horse had greater acceleration? a. horse a because its change in velocity was greater than horse b in the same time. b. horse b because its change in velocity was greater than horse a in the same time. c. horse b because its change in velocity was the same as horse a's, but it took less time. d. both horses had the same acceleration.

The answer is B

Given that,

Initial velocity of both horses are zero. (at rest)

Final velocity of Horse A= 10m/s

final velocity of Horse B= 13 m/s

Acceleration for horse A will be,

a = ΔV/t= 10/t

Acceleration for horse B will be,

a= ΔV/t= 13/t

Therefore, Horse B have greater acceleration because its change in velocity was greater than Horse A in the same time.

im not to sure what it is

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .