Aball is projected at an angle of 53. if the initial velocity is the 48 meters/seconds, what is the vertical component of the velocity with which it was launched?

28.89 m/s

Explanation:

A vector quantity can be resolved into two components.

1. Horizontal component

2. Vertical component

Let there is a vector R which makes an angle theta from X axis.

Its component along X axis is given by R Cos theta and the component along Y axis is given by R Sin theta.

SI, the vertical component of velocity is

Vx = 48 × Cos 53

Vx = 28.89 m/s

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

spare some change and give it to the poor

explanation:

plz : ((