Ashout down a well produces an echo in 2.00 seconds. how deep is the surface of the water in the well? assume the speed of sound to be 343 m/s.

t = total time taken by sound to go down the well and then come back = 2 sec

d = depth of the well

D = total distance traveled by the sound

total distance traveled by sound is given as

total distance traveled = distance traveled going down + distance traveled going up

D = d + d

D = 2 d                                                               eq-1

v = speed of sound = 343 m/s

we know that distance traveled is given as

total distance traveled = speed of sound x total time

D = v t

using eq-1

2 d = v t

2 d = (343) (2)

dividing both side by 2

d = 343 x 2/2

d = 343 m

hence surface of water is 343 m deep

grav potential energy