The force required to stretch a hooke’s-law spring varies from 0 n to 62.4 n as we stretch the spring by moving one end 17.2 cm from its unstressed position. find the force constant of the spring. answer in units of n/m. find the work done in stretching the spring. answer in units of j.

I think this is correct, but I am not entirely certain.

Find the force constant of the spring:

F = - KX

(0 - 62.4) = -K(0.172m)

-362.791 = -K

362.791 N/m = K

Find the work done in stretching the spring:

W = (1/2)KX

W = (1/2)(362.791)(0.172m)

W = 31.2 J

hey , the answer is c

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example