The density of mercury is 1.36 × 10 by 4 kgm - 3 at 0 degrees. calculate its value at 100 degrees and at 22 degrees. take cubic expansivity of mercury as equal to 180 × 10-6 k -1

a) Density at 100 degrees:

Explanation:

The density of mercury at 0 degrees is

Let's take 1 kg of mercury. Its volume at 0 degrees is

The formula to calculate the volumetric expansion of the mercury is:

where

is the cubic expansivity of mercury

V is the initial volume

is the increase in temperature

In this part of the problem,

So, the expansion is

So, the new density is

b) Density at 22 degrees:

We can apply the same formula we used before, the only difference here is that the increase in temperature is

And the volumetric expansion is

So, the new density is

i think if it were me i whould divide 300 dide 15

step-by-step explanation: