The initial vertical component of the velocity is 15.3 m/s and the angle of the water is 55 degrees. what is the magnitude of the vector? the answer is 18.7 m/s but how did they get

The vertical component of velocity is given by

V = Vy x Sin (Theta)

15.3 m/s = Vy x Sin (55 degrees)

Vy = 15.3 m/s/Sin (55 degrees)

= 15.3 m/s/0.819

= 18.681 m/s

18.7 m/s

Explanation:

1. Use the equation V = Vy x Sin(Theta) then plug in your numbers.

15.3 m/s = Vy x Sin(55 degrees)

2. then switch em up so we can have the Vy isolated and the 15.3 m/s as part of the equation.

3. Now that multiplication sign turns to a division sign.

Vy = 15.3 m/s / Sin(55 degrees)

4. and if you plug it in you get your answer after rounding it

Vy = 18.7

f=ma newton's second law 7x8=56n

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