Astudent produces a power of p = 0.87 kw while pushing a block of mass m = 75 kg on an inclined surface making an angle of î¸ = 8.5 degrees with respect to the horizontal. the coefficient of kinetic friction between the block and the incline is î¼k = 0.16. randomized variables p = 0.87 kw m = 75 kg î¸ = 8.5 degrees î¼k = 0.16 50% part (a) write an expression for the maximum constant speed, vm, the block travels at under the power applied by the student.

The maximum constant speed of block under the power applied by the student is 3.86 m/s.

Given data:

The magnitude of power is, P = 0.87 kW = 870 W.

The mass of block is, m = 75 kg.

Angle of inclination with horizontal is, .

The  coefficient of kinetic friction between the block and incline is, .

he expression for the net force on the block at incline is,

The expression for the power is,

Here, v is the maximum constant speed of block under the power applied by the student.

Solving as,

Thus, the maximum constant speed of block under the power applied by the student is 3.86 m/s.

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When block is pushed upwards along the inclined plane

the net force applied on the block will be given as

here we know that

m = 75 kg

now plug in all values into this

now for finding the power is given as

12000j is work done

the answer is b i think