Abody weighs 160n in air and 120n when wholly immersed in a liquid of relative density 0.8. the relative density value of the body is (g=10ms-2) (a)2.2 (b)3.2 (c)1.2 (d)3.8

W = weight of the body in air = 160 N

ρ' = density of body

V = volume of the body

weight of the body in air  is given as

W = ρ' V g                                       eq-1

W' = weight of the body in liquid = 120 N

force of buoyancy is given as

F = W - W'

F = 160 - 120

F = 40 N

ρ = density of liquid = ?

force of buoyancy is given as

F = ρ V g                                               eq-2

dividing eq-1 by eq-2

160/40 =  ρ' V g /(ρ V g )

4 =  ρ' /(0.8 )

ρ' = 3.2

(b)3.2

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explanation:

i'm only doing this the points

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