Butane burns as shown in the balance chemical equation 2c4h10+13o2=10h2o+8co2. if 6 mol of butane of carbon dioxide are produced

balance equation is given as

2 C₄H₁₀+ 13 O₂ = 10 H₂ O + 8 CO₂

since 6 mol of butane is burns , we multiply both side by "3"  as  3 x 2 = 6

multiplying each term by "3"

(3 x 2) C₄H₁₀+ (13 x 3) O₂ = (10 x 3) H₂ O + (8 x 3) CO₂

6 C₄H₁₀ + 39 O₂ = 30 H₂ O + 24 CO₂

from the equation , we see that when 6 moles of butane are burnt , we get 24 moles of carbon dioxide

tbh i dont know ether

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)