Aweightlifter raises a barbell of mass 100 kg from the floor to over his head ( 2.5 meters) in 2 seconds. what is his average power input? give ur answer in both watts and horse power

bear in mind that Gravitational capacity potential = mass * height * g. So, a) (i) artwork achieved = substitute in potential = a hundred * 9.80 two * 2 = 1964 J (ii) The sideways movements make no distinction to the terrific artwork achieved. the burden nonetheless finally ends up 2 m from the floor, so the comparable volume of artwork must be achieved. artwork achieved = 1964 J b) whilst the burden is released, its PE is switched over into Kinetic potential. So, on the instantaneous beforehand is hits his toe, we've 1964 = (a million/2) m v^2 v^2 = 1964 / (0.5 * a hundred) = 39.28 v = ?(39.28) = 6.27 m/s

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation:

we need answer choices