A2.0 kilogram object is falling freely near earth's surface. what is the magnitude of the gravitational force that earth exerts on the object

The correct answer to the question is : 19.6 N.

EXPLANATION :

As per the question, the mass of the object m = 2.0 Kg.

The object is falling near the earth's surface.

We are asked to calculate the gravitational force.

The gravitational force exerted by earth on the object is equal to the weight of the body. It is so because the weight of the body is the force with which any body on the surface of earth is attracted towards the centre of earth.

The weight of the body is calculated as-

                     Weight W = mg

Here, g is known as the acceleration due to gravity and g =

Hence, weight of the body W = 2 × 9.8 N.

                                                 = 19.6 N.

Hence, the gravitational force on the object is 19.6 N.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

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