An air pump does 5,600 j of work to launch a water bottle rocket into the air. if the air pump applies 150 n of force to the rocket at an angle of 45° to the ground, what is the horizontal distance the water bottle rocket travels? round your answer to two significant figures.

5.3 × 10^1 m

Explanation:

53 m

Explanation:

Work = Force × Displacement

W= F s cosΘ

Where, s is the displacement and F is the force. Θ is the angle between force and displacement

F cosθ is the component of force acting in the horizontal direction.

The air pump applies F = 150 N force at an angle Θ = 45°

W = 5600 J

⇒s = W/F cosθ

Thus, the horizontal distance the water bottle rocket travels is 53 m

volume: 22

density: 7.04

car a and b are moving in opposite directions

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