Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it

2N/cm

Step-by-step explanation:

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

where, is the force which is stretching or compressing the spring,

is the spring constant; and

is the distance the spring is stretched.

Substituting the given values to find the elastic constant   to get:

Therefore, the elastic constant is 2 Newton/cm.

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.