Block a is accelerating with block b at a rate of 0.800 m/s2 along a frictionless surface. it suddenly encounters a surface that supplies 25.0 n a friction. what is the new acceleration? a. 0.4 m/s2 b. 1.0 m/s2 c. 0.8 m/s2 d. 0.6 m/s2

Explanation:

The attached figure shows the whole description. Considering the applied force is 100 N.

The acceleration of both blocks A and B,

Firstly calculating the mass m using the second law of motion as :

F = ma

m is the mass

m = 125 kg

It suddenly encounters a surface that supplies 25.0 N a friction, F' = 25 N

So, the new acceleration of the block is . Hence, this is the required solution.

not too sure thinking all accelerations are pointed down