Abowling bowl is thrown off the top of a building. determine distance the ball has fallen after falling for 3.0 s. remember, the gravitational acceleration (g) is 9.8 m/s2. (hint: d = ½gt2)

consider the motion of the bowling ball along the vertical direction after it is thrown off.

assuming down direction as positive.

Y = vertical displacement of the bowling ball = distance traveled downward = d

a = acceleration of the ball = acceleration due to gravity = 9.8 m/s²

t = time of travel = 3.0 s

v₀ = initial velocity of the ball along the vertical direction = 0 m/s

using the equation

Y = v₀ t + (0.5) a t²

d = 0 (3.0) + (0.5) (9.8) (3.0)²

d = (0.5) (9.8) (9.0)

d = 44.1 m

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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