A1 kg brick is dropped from a height of 10 m. calculate the work that has been done on the brick between the moment it is released and the moment when it hits the ground. neglect air resistance.

Work can be defined as the transformation of energy released during the movement of an object when an external force is applied to the object.  

The work done by the brick is 98 Joules.

Given that the mass m of the brick is 1 kg and it dropped from a height h of 10 m. In this case, gravitational acceleration will be 9.8 m/s. Now to calculate the work done by the brick, we apply the work-energy theorem.  

The work-energy theorem states that the work done by all the forces on the object is equivalent to the total change in the kinetic energy during the movement.

Work done by the brick = Work done by gravity + Work done by air resistance

Apply that the air resistance is negligible then,

Work done by the brick = Work done by the gravity

Work Done =

Work =

Work = .

Hence we can conclude that the work done by the brick during the movement is 98 Joules.

To know more about the work, follow the link given below.

link.

The work done on the brick during its fall is exactly the work that was done on it to lift it up to the height of 10m in the first place, AND it's the gravitational potential energy it has while it's up there.

Gravitational Potential Energy = (mass) x (gravity) x (height)

GPE of the brick = (1 kg) x (9.8 m/s²) x (10 m)

GPE = (1 x 9.8 x 10) (kg-m² /s²)

GPE = 98 Joules

From the time it drops off the 10m shelf until it hits the ground, 98 Joules of work is done on it.

What does the work ?  Where does that energy come from ?

GRAVITY does the work on the brick !

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