While racing on a flat track a car rounds a curve of 56m radius and instantaneously experiences a centripetal acceleration of 36 m/s how fast was the car going. 25m/s 45m/s 35m/s 2.0 x 10^3 m/s

45m/s should be the answer because the acceleration changes into's velocity and goes towards the centre in which  is 56/ms that equals v^2/R  the speed at the instant.

Hope this helped

Regards, ShaggySnaps

your answer is, orbit around the nucleus

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west