Aspring, when compressed 0.20 m from the equilibrium position, stores 24 j. what is the value of the spring constant

Given that:

spring compressed ( x) = 0.2 m

                        Work (W) = 24 J

 determine , spring constant (x)=?

               We know hat ,

                      Work   (W) = (1/2). k.x²

                                   24 = 1/2 ( k × 0.2²)

                                     48 = k × 0.2²

                                      k = 1200 N/m

because growing process had stoped after 4-5 year

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer