How much he is given out 185 g of lead cools from 200 celsius to 10 celsius

Given data

mass (m) = 185 g  = 0.185 Kg ,

temperature (T₁) = 200°C = 200 + 273 = 473 K

temperature (T₂) = 10°C = 10+273 = 283 K

Specific haet at constant pressure (Cp) = 2.108 Kj/Kg k

                Heat transfer (Q) = m.Cp.( T₂- T₁) J

                                            = 0.185 × 2.108 × (283 - 473)

                                         Q = -74.09 KJ

Heat rejected from ice is 74 J

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.